week 3 practice

1. Find the area under the standard normal curve. Round to four decimal places.

 

Question

Answer

a. between z = 0 and z = 1.95 .9744
b. between z = 0 and z = −2.05  
c. between z = 1.15 and z = 2.37  
d. from z = −1.53 to z = −2.88  

 

 

 

2. The F distribution is:

 

Question

Answer

a. Discrete or continuous?  
b. Symmetrical, skewed to the right, or skewed to the left?  
c. Like the normal or Z distribution, the F distribution can have negative values. True or False?  

 

 

 

3. Find the critical value of F for the following. Round to two decimal places.

 

Question

Answer

a. df = (3, 3) and area in the right tail = .05  
b. df = (3, 10) and area in the right tail = .05  
c. df = (3, 30) and area in the right tail = .05  

 

 

 

4. The following ANOVA table is based on information obtained for three samples selected from three independent populations that are normally distributed with equal variances. You have all of the information you need (below) to fill in the six missing values (Roman numerals). The intermediate numbers must correctly result in F = 2.16. Round to four decimal places and mark with bold. Use Tables 12.3 and 12.4 (p. 498) as a guide.

 

 

 

Source of

Variation

Degrees of

Freedom

Sum of

Squares

Mean

Square

Value of the

Test Statistic

Between

2

II

19.2813

Within

89.3677

III

F = ___V__ = 2.16

              VI

Total

12

IV

 

 

 

5. Using F = 2.16 and α = .01, what is your conclusion regarding

 

Ho: the means of the three populations are all equal

 

Ha: the means of the three populations are not all equal?

 

Use Table VII critical values of F for .01 (p. B24). (One choice is TRUE; the other three are FALSE.)

 

 

 

Question

Answer

a. Reject H0. Conclude that the means of the three populations are equal.  
b. Reject H0. Conclude that the means of the three populations are not equal.  
c. Do not reject H0. Conclude that the means of the three populations are equal.  
d. Do not reject H0. Conclude that the means are of the three populations are not equal.  

 

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